atoti.date_diff()#

atoti.date_diff(from_date, to_date, /, *, unit='days')#

Return a measure equal to the difference between two dates.

The measure evaluates to None if one of the dates is None.

Parameters:

  • from_date (_DateOrNonConstantMeasureConvertible) – The starting date.

  • to_date (_DateOrNonConstantMeasureConvertible) – The end date.

  • unit (Literal['seconds', 'minutes', 'hours', 'days', 'weeks', 'months', 'years']) – The difference unit. Seconds, minutes, and hours are only allowed if the dates contain time information.

Return type:

MeasureDescription

Example

>>> from datetime import date
>>> df = pd.DataFrame(
...     columns=["From", "To"],
...     data=[
...         (date(2020, 1, 1), date(2020, 1, 2)),
...         (date(2020, 2, 1), date(2020, 2, 21)),
...         (date(2020, 3, 20), None),
...         (date(2020, 5, 15), date(2020, 4, 15)),
...     ],
... )
>>> table = session.read_pandas(
...     df, table_name="date_diff example", default_values={"To": None}
... )
>>> cube = session.create_cube(table)
>>> l, m = cube.levels, cube.measures
>>> m["To"] = tt.agg.single_value(table["To"])
>>> m["Diff"] = tt.date_diff(l["From"], m["To"])
>>> cube.query(m["To"], m["Diff"], levels=[l["From"]], include_empty_rows=True)
                    To Diff
From
2020-01-01  2020-01-02    1
2020-02-01  2020-02-21   20
2020-03-20
2020-05-15  2020-04-15  -30