atoti.agg.min_member()#
- atoti.agg.min_member(measure, /, level)#
Return a measure equal to the member minimizing the passed measure on the given level.
When multiple members minimize the passed measure, the first one (according to the order of the given level) is returned.
- Parameters:
measure (VariableMeasureConvertible) – The measure to minimize.
level (Level) – The level on which the minimizing member is searched for.
- Return type:
MeasureDescription
Example
>>> df = pd.DataFrame( ... columns=["Continent", "City", "Price"], ... data=[ ... ("Europe", "Paris", 200.0), ... ("Europe", "Berlin", 150.0), ... ("Europe", "London", 240.0), ... ("North America", "New York", 270.0), ... ], ... ) >>> table = session.read_pandas( ... df, ... table_name="City price table", ... ) >>> table.head() Continent City Price 0 Europe Paris 200.0 1 Europe Berlin 150.0 2 Europe London 240.0 3 North America New York 270.0 >>> cube = session.create_cube(table, mode="manual") >>> h, l, m = cube.hierarchies, cube.levels, cube.measures >>> h["Geography"] = [table["Continent"], table["City"]] >>> m["Price"] = tt.agg.single_value(table["Price"]) >>> m["City with minimum price"] = tt.agg.min_member(m["Price"], l["City"])
At the given level, the measure is equal to the current member of the City level:
>>> cube.query(m["City with minimum price"], levels=[l["City"]]) City with minimum price Continent City Europe Berlin Berlin London London Paris Paris North America New York New York
At a level above it, the measure is equal to the city of each continent with the minimum price:
>>> cube.query(m["City with minimum price"], levels=[l["Continent"]]) City with minimum price Continent Europe Berlin North America New York
At the top level, the measure is equal to the city with the minimum price across all continents:
>>> cube.query(m["City with minimum price"]) City with minimum price 0 Berlin