atoti.Level.isin()#
- Level.isin(*members)#
Return a condition to check that the level is on one of the given members.
level.isin(a, b)
is equivalent to(level == a) | (level == b)
.- Parameters:
members (ConstantValue) – One or more members on which the level should be.
- Return type:
Condition[LevelIdentifier, Literal[‘isin’], Constant, None]
Example
>>> df = pd.DataFrame( ... columns=["City", "Price"], ... data=[ ... ("Berlin", 150.0), ... ("London", 240.0), ... ("New York", 270.0), ... ("Paris", 200.0), ... ], ... ) >>> table = session.read_pandas(df, keys=["City"], table_name="isin example") >>> cube = session.create_cube(table) >>> l, m = cube.levels, cube.measures >>> m["Price.SUM in London and Paris"] = tt.filter( ... m["Price.SUM"], l["City"].isin("London", "Paris") ... ) >>> cube.query( ... m["Price.SUM"], ... m["Price.SUM in London and Paris"], ... levels=[l["City"]], ... ) Price.SUM Price.SUM in London and Paris City Berlin 150.00 London 240.00 240.00 New York 270.00 Paris 200.00 200.00